Problema Solution
A ball is thrown from a height of 80 feet with an initial downward velocity of 4ft/s. The ball's h (in feet) after t seconds is given by the following.
h=80-4t-16t^2
How long is after the ball is thrown does it hit the ground?
Answer provided by our tutors
h=80-4t-16t^2
We need to find for what positive value of t, h =0, that is:
80-4t-16t^2 = 0
........
click here to see the equation solved for t
........
t = 2.11 s
The ball will hit the ground after 2.11 seconds.