Problema Solution

Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest, the result is 2 more than twice the middle integer.

Answer provided by our tutors

let '2n' represent the first even integer, then '2n+2' and '2n+4' represent the next two consecutive even integers


largest integer is subtracted from four times the smallest:

4(2n) - (2n+4) = 8n-2n-4 = 6n-4


2 more than twice the middle integer:

2(2n+2) + 2 = 4n+6


we set the two statements equal to each other and solve for 'n':

6n-4 = 4n+6

2n=10

n=5


2*5 = 10


The integers are 10, 12 and 14.