Problema Solution
Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest, the result is 2 more than twice the middle integer.
Answer provided by our tutors
let '2n' represent the first even integer, then '2n+2' and '2n+4' represent the next two consecutive even integers
largest integer is subtracted from four times the smallest:
4(2n) - (2n+4) = 8n-2n-4 = 6n-4
2 more than twice the middle integer:
2(2n+2) + 2 = 4n+6
we set the two statements equal to each other and solve for 'n':
6n-4 = 4n+6
2n=10
n=5
2*5 = 10
The integers are 10, 12 and 14.