Problema Solution
A model rocket is launched with an initial upward velocity of
47ft/s The rocket's height h (in feet) after t seconds is given by the following.
h= 47t-5t^2
Find all values of t for which the rocket's height is 27 feet.
Answer provided by our tutors
The rockets height is given by
h(t) = 47t-5t^2
We want to find all the values of t so that h(t) = 27 ft, that is, we need to solve the quadratic equation:
47t-5t^2 = 27
........
click here to see the step by step solution for t
........
t1 = 0.6 s
t2 = 8.8 s
The rocket will be at 27 ft height 0.6 s and 8.8 s after the launching.