Problema Solution

A ball is thrown from an initial height of

3

meters with an initial upward velocity of

13/ms

. The ball's height

h

(in meters) after

t

seconds is given by the following.

=h+3−13t5t2

Find all values of

t

for which the ball's height is

10

meters.

Answer provided by our tutors

We will assume that h=3 - 13t - 5t^2.

We need to find for what positive value of t, h =10, that is:

3 - 13t - 5t^2 = 10

........

click here to see the equation solved for t

........

t1 = - 0.76

t2 = - 1.84

Since the solutions are negative and the time must be positive follows the ball will never reach the height of 10 meters.