Problema Solution
A ball is thrown from an initial height of
3
meters with an initial upward velocity of
13/ms
. The ball's height
h
(in meters) after
t
seconds is given by the following.
=h+3−13t5t2
Find all values of
t
for which the ball's height is
10
meters.
Answer provided by our tutors
We will assume that h=3 - 13t - 5t^2.
We need to find for what positive value of t, h =10, that is:
3 - 13t - 5t^2 = 10
........
click here to see the equation solved for t
........
t1 = - 0.76
t2 = - 1.84
Since the solutions are negative and the time must be positive follows the ball will never reach the height of 10 meters.