Problema Solution
The half-life of a radioactive kind of indium is 3 days. How much will be left after 6 days, if you start with 88 grams of it?
Answer provided by our tutors
The formula for determining the amount of substance left is:
A=Ce^(kt), where C is the initial amount, k is the decay constant, and t is time.
Given the half-life of t=3 days we have:
C/2=Ce^(3k)
½=e^(3k)
Taking log both sides:
Ln(1/2)=ln(e^(3k)
-0.693=3k
k=-0.693/3
k=-0.231049
Amount after t = 6 days and C = 88 grams initial amount:
A=88*e^((-0.693/3)*6)
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click here to see the calculation for A
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A= 22 grams
After 6 days there will be 22 grams of indium left.