Problema Solution

what is the smallest positive integer for x, so that the value of f(x)=200(2)^x is greater than the value of g(x)=500x + 400?

Answer provided by our tutors

f(x) > g(x)

200(2)^x > 500x + 400

For x = 4 we have:

200*2^4 = 3200

500*4 + 400 = 2400

For x = 4 we have f(4) > g(4).

For x = 3 we have:

200*2^3 = 1600

500*3 + 400 = 1900

The means f(3) < g(3).

The answer is x = 4 is the smallest positive integer such that f(4) > g(4).