Problema Solution
what is the smallest positive integer for x, so that the value of f(x)=200(2)^x is greater than the value of g(x)=500x + 400?
Answer provided by our tutors
f(x) > g(x)
200(2)^x > 500x + 400
For x = 4 we have:
200*2^4 = 3200
500*4 + 400 = 2400
For x = 4 we have f(4) > g(4).
For x = 3 we have:
200*2^3 = 1600
500*3 + 400 = 1900
The means f(3) < g(3).
The answer is x = 4 is the smallest positive integer such that f(4) > g(4).