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Parabola - How it opens: Graph, focus, direction, vertex, axis and directrix

Original question text:

Please help me in parabola problem.

This is my assignment:

How to graph this parabola and what is the focus, direction, vertex, axis of parabola, directrix and latus rectum.

Please help me to understand this question.

4y^2=-3x and -3x^2=15y

Thanks! ! !! ! ! !

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How can Algebrator help you with this problem?

This is Part 3 of your problem.

There also is a specific Wizard in order to find out how a Parabola equation opens.

You simply have to open the "Parabola Wizard" and select the "Determine if a Parabola Opens up, down, left or right" option.

You then enter the Parabola´s equation and press the "Solve" button.

This is Part 3 of your problem. There also is a specific Wizard in order to find out how a Parabola equation opens. You simply have to open the "Parabola Wizard" and select the "Determine if a Parabola Opens up, down, left or right" option. You then enter the Parabola´s equation and press the "Solve" button.


Parabola - How it opens: Graph, focus, direction, vertex, axis and directrix


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