Vertex of a Parabola
Original question text:
What is the turning point of the parabola whose equation is y= -x^2 -4x +3?
Please show work so I can learn how to do it myself! Thank you!How can Algebrator help you with this problem?
Algebrator can easily solve problems such as the one you posted on Yahoo Answers.
Finding the Vertex of a Parabola is one of the many tasks available on the Wizard menu.
An example using your equation is described below.
You must first start by entering the Equation.
First we have to solve the non-linear equation.
Clicking on the "Solve step" button once shows the first step of the solution process.
Algebrator then rearranges the terms in this equation.
Explanation for this (or any other) step is just a click away.
Some Important features are:
1.Flash demos, found under the drop-down menu "Help->Tutors".
The demos are also available online at "https://softmath.com/demos/", where you may simply select any of the ".htm"
files and the demo will play within your browser
2. Wizard button - for example, click the Wizard button and look under the category of "Parabola" to see the many useful
templates for Parabola equations.
3. The Explain button, which provides the mathematical logic involved in the selected step.
Algebrator now uses the Square of the binomial formula.
Please check the explanation below.
You can see the rest of the step-by-step solution process by clicking on the "solve step" button several times.
An explanation can be obtained everytime you press the "Explain" button.
We can read the "vertex" directly form the equation.
In our example the vertex is equal to (-2, 7).
Finally you can also see the graphical representation of the solution.
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