Problema Solution
A 20% concentrate is to be mixed with a mixture having a concentration of 60% to obtain 80 liters of a mixture with a concentrate of 30%. How much of the 20% concentrate and the 60% concentrate will be needed?
Answer provided by our tutors
Let
x = liters of the 20% concentrate, x>=0
y = liters of the 60% concentrate, y>=0
The mixture is 80 liters with 30% concentration:
x + y = 80
0.20x + 0.60y = 0.30*80
........
click here to see the system of equations solved for x and y
........
x = 60 L
y = 20 L
60 liters of the 20% concentrate and 20 liters of he 60% concentrate is needed.