Problema Solution
A 56ft rope was cut into 3 pieces. Every second piece is twice as long as the previous. Find the length of the smaller piece.
Answer provided by our tutors
let 'x' represent the smallest length, then '2x' represents the second longest length and '4x' represents the longest length
56 = x + 2x + 4x
-------------------
-------------------
x=8
2*8 = 16
4*8 = 32
The smallest piece is 8 ft (the second is 16 ft and the third piece is 32 ft).
let 'x' represent the smallest length, then '2x' represents the second longest length and '4x' represents the longest length
56 = x + 2x + 4x
corrected URL:
x=8
2*8 = 16
4*8 = 32
The smallest piece is 8 ft (the second is 16 ft and the third piece is 32 ft).