Problema Solution
A ball is thrown upward at 88 feet per second from a building 3232 feet high. Use the formula below where h is the final height in feet, t is the time of travel in seconds, v0 is the initial velocity in feet per second, and h0 is the initial height in feet of an object traveling upward. When will the ball be 88 feet above the ground?
h equals negative 16 t squared plus v 0 t plus h 0h=−16t2+v0t+h0
Answer provided by our tutors
h=−16t^2+v0t+h0
v0 = 88 ft/s
h0 = 3232 ft
h = 88 ft
t = ?
We need to find t, t>=0, by solving the following equation:
-16t^2 + 88t + 3232 = 88
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click here to see the equation solved for t
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t = 17.04 s
We need to ignore the negative solution since the time can not be negative.
After 17.04 seconds the ball will be 88 feet above the ground.