Problema Solution
A ball is thrown vertically upward within an initial velocity of 48feet per second. If the ball started from a height of 8 feet off the ground, determine the time it will take for the ball to hit the ground.
Answer provided by our tutors
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by the equation:
h=-16t^2+vt+s (where h and s are in ft, t is in seconds and v is in ft/sec).
In our case we have:
v = 48 ft/s
s = 8 ft
h = -16t^2 + 48t + 8
We need to find t, t>0 such that h = 0 (the ball hits the ground):
-16t^2 + 48t + 8 = 0
........
click here to see the equation solved for t
........
t = 3.16 s
The ball will hit the ground after 3.16 seconds.