Problema Solution
A big bug ate 135 smaller bugs in 6 days. Each day it ate 5 more bugs than it did on the previous day. How many small bugs did the big bug eat on the 3rd day? 5th day?
Answer provided by our tutors
1st day the big bug ate: x bugs
2nd day: x + 5
3rd day: x + 5 + 5 = x + 2*5
4th day: x + 2*5 + 5 = x + 3*5
5th day: x + 3*5 + 5 = x + 4*5
6th day: x + 4*5 + 5 = x + 5*5
Altogether 135 smaller bugs or:
x + x + 5 + x + 2*5 + x + 3*5 + x + 4*5 + x + 5*5 = 135
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click here to see the equation solved for x
x = 10
x + 2*5 = 10 + 10 = 20 bugs on the 3rd day
x + 4*5 = 10 + 20 = 30 bugs on the 5th day