Problema Solution
A caterer for a wedding reception charges $53 for a beef dinner, $35 for a chicken dinner, and $49 for a fish dinner. Twice as many beef dinners as fish dinners were ordered. In all, 173 dinners were ordered for the reception and the total bill was $8005. How many of each dinner were ordered?
Answer provided by our tutors
Let
x = the number of fish dinners
2x = beef dinners
173 - (x + 2x) = 173 - 3x the number of chicken dinners
49x + 53*2x + 35*(173 - 3x) = 8005
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click here to see the equation solved for x
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x = 39 fish dinners
2*39 = 78 beef dinners
173 - (39 + 78) = 56 chicken dinners
There were 39 fish, 78 beef and 56 chicken dinners ordered.