Problema Solution
A chemsit has one solution that is 40% acid and a second that is 32% acid .How many liters of each should be mixed together to get 16L that is 38% acid
Answer provided by our tutors
Let
x = liters of 40% acid solution
y = liters of 32% acid solution
x + y = 16
0.40x + 0.32y = 0.38*16
........
Click here to see the step by step solution for the system of equations
........
x = 12 l of 40% acid solution
y = 4 l of 32% acid solution
12 liters of 40% acid solution and 4 liters of 32% acid solution should be mixed together.