Problema Solution
A coin collection has 33 quarters and nickels .The number of nickels is 5 greater than three times the number of quarters .How many coins of each type are there solving using elimination
Answer provided by our tutors
Let
x = the number of quarters
5 + 3x = the number of nickles
x + 5 + 3x = 33
........
click here to see the equation solved for x
........
x = 7 quarters
5 + 3*7 = 26 nickles
There are 7 quarters and 26 nickles.