Problema Solution

A cyclist rode the first 28​-mile portion of his workout at a constant speed. For the 20​-mile cooldown portion of his​ workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the​ cyclist's speed during the first portion and find his speed during the cooldown portion.

Answer provided by our tutors

28/x = 20/(x - 4)
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click here to see the equation solved for x

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x = 14 mph cyclist's speed during the first portion
14 - 4 = 10 mph cyclist's speed during the cooldown portion