Problema Solution
A developer wants to enclose a rectangular grassy lot that borders the city street for parking. If he has 236 fee of fencing and does not fence the side along the street, what is the largest area that can be enclosed?
Answer provided by our tutors
let 'l' represent one of the fenced portion, then the unfenced portion can also be reprsented at 'l' and the total perimeter of the area would be '236+l'
the area would be length * width, so let 'l' represent the length and then width would be "((236+l)-2l)/2"
the area is formulated as follows:
A = l*(236-l)/2
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...the apex of the final graph is 118
the width:
w = (236-118)/2
w=59
the width of the fence would be 59 feet, the single long side would be 118 feet