Problema Solution
A football field is a rectangle 100 yds x 50 yards. What is the area and perimeter in yards and feet? How many classrooms 20 ft. x 25 ft can fit on this football field?
Answer provided by our tutors
1 yd = 3 ft
1 yd^2 = 3^2 ft^2
1 yd^2 = 9 ft^2
The perimeter in yards is:
P = 2*100 + 2*50
P = 300 yd
In feet:
P = 300*3 ft
P = 900 ft
The area in square yards is:
A = 100*50
A = 5000 yd^2
In square feet:
A = 5000*9 ft^2
A = 45,000 ft^2