Problema Solution
a full 6 quart radiator contains 75% water and 25% pure antifreeze. How much of this mixture should be drained and replaced by pure antifreeze so the resulting mixture is 50% pure antifreeze?
Answer provided by our tutors
Let 'x' represet the amount of the mixture that should be replaced by 100% of antifreeze.
0.25*(6 - x) + 1*x = 6*0.50
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click here to see the equation solved for x
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x = 2 quart
2 quart of the mixture should be drained and replace with 100% pure antifreeze.