Problema Solution
A mechanic has found that a car with a 16 quart radiator has 40% antifreeze mixture in the radiator. He has a 80% antifreeze solution. How much of the 40% solution would he have to replace with the 80% solution to get the radiator up to 65% antifreeze solution?
Answer provided by our tutors
Let 'x' represent the quarts of the 40% solution that needs to be replaced with the 80% solution.
0.40(16 - x) + 0.80x = 0.65*16
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x = 10 qt
10 quarts of the 40% solution needs to be replaced with the 80% solution to get the radiator up to 65% antifreeze solution.