Problema Solution
A metallurgist has one alloy containing 24% aluminum and another containing 49% aluminum. How many pounds of each alloy must he use to make 59 pounds of a third alloy containing 29% aluminum? (Round to two decimal places if necessary.)
Answer provided by our tutors
Let
x = pounds of the 24% aluminum alloy
y = pounds of the 49% aluminum alloy
We have the following system of equations:
x + y = 59
0.24x + 0.49y = 0.29*59
........
click here to see the system of equations solved for x and y
........
x = 47.2 lbs
y = 11.8 lbs
47.2 pounds of the 24% aluminum alloy and 11.8 pounds of the 49% aluminum alloy must be used.