Problema Solution
A newspaper carrier has 7.00 in change. He had eight more quarters than dimes but five times as many nickles as quarters. How many coins of each type does he have?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
$7.00 = 700 cents
Let
n = the number of nickels, n>0, n is integer
d = the number of dimes, d>0, d is integer
q = the number of quarters, q>0, q is integer
5n + 10d + 25q =700
q = d + 8
n = 5q
........
click here to see the system of equations solved for n, d and q
........
n = 65 nickles
d = 5 dimes
q = 13 quarters
The newspaper carrier had 65 nickles, 5 dimes and 13 quarters.