Problema Solution
A person opens his wallet and finds that all the bills are $1 bills, $5 bills, or $10 bills. There are 35 bills in this person's wallet. There are 22 more $5 bills than $1 bills. If the total amount of bills is $200, how many $10 bills does this person have?
Answer provided by our tutors
Let
x = the number of $1 bills
y = the number of $5 bills
z = the number of $10 bills
x + y + z = 35 (since there are 35 bills in total)
y = x + 2 (since there are 2 more $5 bills than $1 bills)
x + 5y + 10z = 200 (since the total amount of the bills is $200)
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click here to see the system of equations solved for x, y and z
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x = 10 $1 bills
y = 12 $5 bills
z = 13 $10 bills
The person has 13 $10 bills.