Problema Solution
A person wishes to build a rectangular fence that will enclose an area of 317 square feet. The width
of the fence is to be 3 feet less than twice its length. Set up and solve an algebraic equation to find the
dimensions of the fence to the nearest tenth of a foot.
Answer provided by our tutors
Let
Length = x, x>=0
Width = 2x - 3
A = 317 ft^2 is the area
Since A = width*length we have:
A = x(2x - 3)
x(2x - 3) = 317
........
click here to see the equation solved for x
........
x = 13.4 ft
2*13.4 - 3 = 23.8 ft
The dimensions of the fence are 13.4 feet and 23.8 feet.