Problema Solution
A positive real number is 4 less than another. If the sum of the squares of the two numbers is 98, find the numbers.
Answer provided by our tutors
Let 'x' and 'y' represent the positive real numbers, and let x>y.
y = x - 4
x^2 + y^2 = 98
Plug y = x - 4 into x^2 + y^2 = 98:
x^2 + (x - 4)^2 = 98
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click here to see the equation solved for x
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x = 8.71
y = 8.71 - 4
y = 3.71
The numbers are 8.71 and 3.71.