Problema Solution
A rectangle has a length 4 m less than twice its width. When 2 m are added to the width , the resulting figure is a square with an area of 64 m^2. Find the dimensions of the original rectangle.
Answer provided by our tutors
Let
x = the width of the original rectangle, x>0
2x - 4 = the length of the original rectangle
When 2 m are added to the width the resulting figure is a square with an area of 64 m^2:
The new width is: x + 2
The area of the new square is:
(x + 2)(2x - 4) = 64
........
click here to see the equation solved for x
........
x = 6 m
We will not take into account the negative solution -6 since the width cannot be a negative number.
2*6 - 4 = 8 m
The dimensions of the original rectangle are 6 m and 8 m.