Problema Solution

A rectangle has a length 4 m less than twice its width. When 2 m are added to the width , the resulting figure is a square with an area of 64 m^2. Find the dimensions of the original rectangle.

Answer provided by our tutors

Let

x = the width of the original rectangle, x>0

2x - 4 = the length of the original rectangle

When 2 m are added to the width the resulting figure is a square with an area of 64 m^2:

The new width is: x + 2

The area of the new square is:

(x + 2)(2x - 4) = 64

........

click here to see the equation solved for x

........

x = 6 m

We will not take into account the negative solution -6 since the width cannot be a negative number.

2*6 - 4 = 8 m

The dimensions of the original rectangle are 6 m and 8 m.