Problema Solution
A rectangle has a perimeter of 8x^2+10x-6 and has a width of 3x^2+4x,what is the length of the rectangle
Answer provided by our tutors
Let 'W' be the width and 'L' be the length of the rectangle. We need to find L.
P = 8x^2+10x-6 is the perimeter
W = 3x^2+4x is the width
We know the perimeter is P = 2(L + W) thus we have:
2(L + 3x^2+4x) = 8x^2+10x-6
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click here to see the equation solved for L
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L = x^2 + x - 3
The length of the rectangle is x^2 + x - 3.