Problema Solution
A rectangle is 2 times as long as it is wide. If the area is 8 square feet, find its perimeter
Answer provided by our tutors
Let
L = the length of the rectangle, L >= 0
W = the width of the rectangle, W >= 0
A rectangle is 2 times as long as it is wide:
L = 2W
The area is 8 square feet:
L*W=8
Plug L = 2W into the last equation:
2W*W = 8
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Click here to see the step by step solution for W
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W = 2 ft
We ignore the negative solution since the width cannot be a negative number.
Now, the length is:
L = 2W
L = 2*2
L = 4 ft
The perimeter 'P' is:
P = 2L + 2W
P = 2*4 + 2*2
P = 12 ft
The perimeter of the rectangle is 12 feet.