Problema Solution

a shipment of 8 computers contains 2 with defects. Find the probability that a sample size of 3, drawn from the 8, will not contain a defective computer.

Answer provided by our tutors

The probability of x defective computer in n trials is:


P = nCx* p%5Ex%2Aq%5E%28n-x%29 where p and q are the probabilities of success and failure respectively.


In our case p(defective) = 2/8 and q(not defective) =6/8 

nCx = n%21%2F%28x%21%28n-x%29%21%29

Since n = 3 and x = 0 we have

nCx = 1

P(no defective computer) = 1*q^n

P(no defective computer) = q^3

P(no defective computer) = (6/8)^3

P(no defective computer) = 0.421875

The probability that a sample size of 3 will not contain a defective computer is  0.421875.