Problema Solution
a shipping company is preparing an order consisting of two different items. the shipping container is 2274 cubic feet and the dimensions of each items are:
Item A: 1 1/3 feet long, 3 2/3 feet wide, and 9 feet deep
Item B: 1.5 feet long, 2 1/3 feet wide, and 6 feet deep
The number of items "A" in the container is five less than half the number of items "B" in the container. If the container is full, how much of each item must be in the container
Answer provided by our tutors
Let 'a' represent the number of items "A" in the container and 'b' represent the number of items "B" in the container.
a = (1/2)b - 5
The volume of item A is: (1 1/3)*(3 2/3)*9 = (4/3)*(11/3)*9 = 44 ft^3
The volume of item B is: 1.5*(2 1/3)*6 = 1.5*(7/3)*6 = 21 ft^3
44a + 21b = 2274
We have the following system of equations:
a = (1/2)b - 5
44a + 21b = 2274
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click here to see the system of equations solved for a and b
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a = 24 items A
b = 58 items B
There are 24 items A and 58 items B in the container.