Problema Solution
A technical machinist is asked to build a cubical steel tank that will hold
275 L of water.
Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest
0.001 m.
Answer provided by our tutors
1 m^3 = 1,000 L
1 L = 1/1000 m^3
275 L = 275/1000 m^3
Let 'x' represent the length of the inside of the tank.
The volume of a cube with length x is x^3:
x^3 = 275/1000
x = 0.65 m
The smallest possible inside length of the tank is 0.65 m.