Problema Solution
An object is thrown upward from the top of a 160- foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h=-16t^2+48t+160. When will the object hit the ground?
Answer provided by our tutors
The object hits the ground when h(t) = 0 for some t, t>0.
By solving h(t) = 0 that is:
-16t^2+48t+160 = 0
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click here to see the equation solved for t
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t = 5 s (We need to ignore the negative solution -2 because the time can only be non-negative)
The object will hit the ground after 5 seconds.