Problema Solution
chary invested an amount at 12% and twice as much at 9%. her annual interest at 9% is 10,140 pesos more than her annual interest on 12%. how much is invested at each rate?
Answer provided by our tutors
Let
x = the amount invested at 12%
2x = the amount invested at 9% (twice as much the amount invested at 12%)
0.09*2x = 10140 + 0.12*x
........
click here to see the equation solved for x
........
x = $169,000
2x = 2*169,000 = $338,000
$338,000 are invested at 9% and $169,000 are invested at 12%.