Problema Solution
compare the total time required to drive a long, tiring day of 500 miles at an avergae speed of 60mph versus an average speed of 70mph. is the time saved for such a long trip worth the added risk of higher speed
Answer provided by our tutors
The time t1 need to drive 500 mi at average speed of 60 mph is:
t1 = d/v (since v = d/t)
t1 = 500/60
t1 = 50/6
t1 = 8 2/6 hr
t1 = 8 hr 20 min
The time t2 need to drive 500 mi at average speed of 70 mph is:
t2 = 500/70
t2 = 50/7
t2 = 7 1/7 hr
t2 = 7 hr 8.6 min
The time saved is: 8 hr 20 min - 7 hr 8.6 min = 1 hr 11.4 min.