Problema Solution
Diane, Rafael, and Hong have a total of $100 in their wallets. Hong has 2 times what Rafael has. Rafael has $8 less than Diane. How much do they have in their wallets?
Answer provided by our tutors
Let
x = the amount of money Diane has, x>=0
x - 8 = the amount of money Rafael has ($8 less that Diane)
2(x - 8) = the amount of money Hong has (2 times of what Rafael has)
The total of money that Diane, Rafael, and Hong altogether is $100:
x + (x - 8) + 2(x - 8) = 100
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click here to see the equation solved for x
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x = $32
Diane has $32.
Rafael has 32 - 8 = $24.
Hong has 2*24 = $48.