Problema Solution

father is four times is as old as his son today .six years ago,the product of the number denoting their ages was 252.find their present age?

Answer provided by our tutors

Let

x = the present age of son, x>=0

y = the present age of father y>=0

Father is 4 times is as old as his son today means:

y = 4x

6 years ago, the product of the number denoting their ages was 252:

(x - 6)(y - 6) = 252

Plug y = 4x into the last equation:

(x - 6)(4x - 6) = 252

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click here to see the equation solved for x

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x = 12 years

y= 4*12 = 48 years

Father's present age is 48 years.

Son's present age is 12 years.