The 2 consecutive odd integers can be written as:

2x - 1 and 2x + 1, where x is integer.

The product of the 2 consecutive odd integers is 11 more than 2 times their sum

(2x - 1)(2x + 1) = 11 + 2*(2x - 1 + 2x + 1)

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click here to see the equation solved for x

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x1 = 3

x2 = -1

For x = 3 we have:

2*3 - 1 = 5

2*3 + 1 = 7

For x = -1 we have:

2*(-1) - 1 = -3

2*(-1) + 1 = -1

We have found two solutions:

The two consecutive odd integers are 5 and 7.

The two consecutive odd integers are -3 and -1.