Problema Solution
find 3 consectuive odd integer susch that thrice the middle is 15 more than the sum of the two.
Answer provided by our tutors
Every odd number can be written in a form 2k +1, where k is integer.
Thus the three consecutive odd integers can be written as:
2k - 1, 2k + 1 and 2k + 3, where k is integer.
Three times the middle is 15 more than the sum of the two:
3(2k + 1) = 15 + 2k - 1 + 2k + 3
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click here to see the equation solved for k
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k = 7
2k - 1 = 2*(7) - 1 = 13
2k + 1 = 2*(7) + 1 = 15
2k + 3 = 2*(7) + 3 = 17
The three consecutive odd integers are 13, 15 and 17.