Problema Solution
Find an equation of the circle that satisfies the given conditions.
Center at the origin; passes through (2, 6)
Answer provided by our tutors
The equation of circle can be written as:
(x – h)^2 + (y – k)^2 = r^2, where the point (h, k) is the center and r is the radius
In our case (h, k) = (0, 0) or h = 0 and k = 0.
We will find the radius r using the Pythagorean Theorem:
r^2 = 2^2 + 6^2
r^2 = 40
The equation of the circle is:
(x - 0)^2 + (y - 0)^2 = 40
x^2 + y^2 = 40
Indeed, check the graph of the circle here