Problema Solution

Find an equation of the circle that satisfies the given conditions.

Center at the origin; passes through (2, 6)

Answer provided by our tutors

The equation of circle can be written as:

(x – h)^2 + (y – k)^2 = r^2, where the point (h, k) is the center and r is the radius

In our case (h, k) = (0, 0) or h = 0 and k = 0.

We will find the radius r using the Pythagorean Theorem:

r^2 = 2^2 + 6^2

r^2 = 40

The equation of the circle is:

(x - 0)^2 + (y - 0)^2 = 40

x^2 + y^2 = 40

Indeed, check the graph of the circle here