Problema Solution
Find four consecutive odd integers such that the sum of two largest integers subtracted from twice the sum of the two smallest integers is 55 more than the largest integer.
Answer provided by our tutors
The four consecutive integers can be written as: x, x+2, x+4 and x+6.
2(x + x + 2) - (x + 6 + x + 4) = 55 + x + 6
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click here to see the equation solved for x
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x = 67
67 + 2 = 69
67 + 4 = 71
67 + 6 = 73
The four consecutive odd integers are 67, 69, 71 and 73.