Problema Solution
Find three consecutive integers such that twice the middle number and five more than the sum of the other two is 53
Answer provided by our tutors
The three consecutive integers can be written as: x - 1, x and x + 1, where x is integer.
x - 1 < x < x + 1
Two times the middle number (x) and five more than the sum of the other two ((x-1) and (x+1)) is 53:
2x + 5 + (x - 1) + (x + 1) = 53
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click here to see the equation solved for x
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x = 12
x - 1 = 12 - 1 = 11
x + 1 = 12 + 1 = 13
The three consecutive integers are 11, 12 and 13.