The 3 consecutive multiples of 4 can be written as:

4(x - 1), 4x, 4(x + 1), where x is integer.

5 times the second is 28 more than 3 times the third can be written as:

5*4x = 28 + 3*4(x + 1)

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click here to see the equation solved for x

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x = 5

4*(5 - 1) = 4*4 = 16

4*5 = 20

4*(5 + 1) = 4*6 = 24

The 3 consecutive multiples of 4 are: 16, 20 and 24.