Problema Solution

Find three consecutive odd integers such that three times the smallest is 27 more than the sum of the other two.

Answer provided by our tutors

The three consecutive odd integers can be written as:


2x - 1, 2x + 1, 2x + 3, where x is integer


2x - 1 is the smallest integer


Three times the smallest is 27 more than the sum of the other two:


3(2x - 1) = 27 + (2x + 1) + (2x + 3)

........

click here to see the step by step solution of the equation

........

x = 17


2*17 - 1 = 33


33 + 2 = 35


35 + 2 = 37


The three consecutive odd integers are 33, 35 and 37.