Problema Solution
Find three consecutive odd integers such that three times the smallest is 27 more than the sum of the other two.
Answer provided by our tutors
The three consecutive odd integers can be written as:
2x - 1, 2x + 1, 2x + 3, where x is integer
2x - 1 is the smallest integer
Three times the smallest is 27 more than the sum of the other two:
3(2x - 1) = 27 + (2x + 1) + (2x + 3)
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x = 17
2*17 - 1 = 33
33 + 2 = 35
35 + 2 = 37
The three consecutive odd integers are 33, 35 and 37.