Problema Solution
Find three consecutive odd integers such that twice the smallest is 3 more than the greatest integer.
Answer provided by our tutors
The three consecutive odd integers can be written as:
2x - 1, 2x + 1 and 2x + 3, where x is integer
The smallest is 2x - 1 and the greatest such integer is 2x + 3.
2(2x - 1) = 3 + (2x + 3)
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click here to see the equation solved for x
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x = 4
2*4 - 1 = 8 - 1 = 7
2*4 + 1 = 9
2*4 + 3 = 11
The three consecutive odd integers are 7, 9 and 11.