Problema Solution
Find two consecutive odd integers such that 3 times the first integer is 5 more than twice the second. (Hint: If x represents the first integer, x + 2 represents the next consecutive odd integer.
Answer provided by our tutors
3x = 5 + 2(x + 2)
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click here to see the equation solved for x
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x = 9
9 + 2 = 11
The two consecutive odd numbers are 9 and 11.