Problema Solution
Find two positive consecutive multiples of 3 such that the sum of their squares is
117
Answer provided by our tutors
The 2 positive consecutive multiples of 3 can be written as: 3x and 3(x + 1), where x is positive integer.
(3x)^2 + (3(x + 1))^2 = 117
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click here to see the equation solved for x
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x = 2
3*2 = 6
3*3 = 9
Indeed 6^2 + 9^2 = 36 + 81 = 117
The solution is 6 and 9.