Problema Solution
first bus leave station traveling 30 mph its passed by second bus that left 5 minutes later doing 35 mph. how far did the first bus travel before it was passed by second bus
Answer provided by our tutors
Let
v1 = 30 mph the speed of the first bus
v2 = 35 mph the speed of the second bus
t = the time of the first bus (in hours)
t - 5/60 = the time of the second bus (in hours)
The formula for distance is: distance = speed*time and since both buses has passed the same distance we have:
v1*t = v2*(t - 5/60)
30t = 35(t - 1/12)
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click here to see the equation solved for t
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t = 7/12 hr
The distance the first bus traveled is:
v1*t = 30*(7/12) = 17.5 miles.