Problema Solution
For the following​ equation, determine what type of number the solutions are and how many solutions exist. x ^2 + 8 x + 4 = 0
Answer provided by our tutors
x^2 + 8 x + 4 = 0
We see that for this equation a = 1, b = 8 and c = 4.
First we need to find the discriminant:
D = b^2 - 4ac
D = 8^2 - 4*1*4
D = 64 - 16
D = 48
Since D > 0 (48 > 0) there are 2 real solutions.