Problema Solution
For the following problem, complete the table to the right. Then solve the problem using a system of equations.
A person wishes to mix coffee worth $18
per lb with coffee worth $6
per lb to get 60
lb of a mixture worth $10
per lb. How many pounds of the $18
and the $6
coffees will be needed?
Answer provided by our tutors
Let
x = lbs of the $18 per lb coffee
y = lbs of the $6 per lb coffee
x + y = 60
18x + 6y = 10*60
........
click here to see the system of equations solved for x and y
........
x = 20 lbs
y = 40 lbs
20 lbs of the $18 per lb and 40 lbs of the $6 per lb coffee will be needed.